p261
DATABACE/MYSQL 2018. 2. 15. 13:25 |1 2 3 4 | use sqldb; select json_object('name', name, 'height', height) AS 'json 값' from usertbl where height >= 180; | cs |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | SET @json = '{ "usertbl" : [ {"name" : "임재범", "hegiht" : 182}, {"name" : "이승기", "hegiht" : 182}, {"name" : "성시경", "hegiht" : 186} ] }'; SELECT JSON_VALID(@json); SELECT JSON_SEARCH(@json, 'one', '성시경'); SELECT JSON_EXTRACT(@json, '$.userTBL[2].name'); SELECT JSON_INSERT(@json, '$.userTBL[0].mDate', '2009-09-09'); SELECT JSON_REPLACE(@json, '$.userTBL[0].name', '홍길동'); SELECT JSON_REMOVE(@json, '$.userTBL[0]'); | cs |
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